Question

Number of waves in a Bohr orbit of H-atom is 3. Its
potential energy would be
(a) - 3.4 eV
(b).- 3.02 eV
(c)-1.51 eV
(d) - 13.6 eV​

Answer 1

Answer:

a.

Explanation:

a should be the answer as per me

Answer 2

The potential energy would be equal to -3.02 eV.

• Since there are 3 waves in the orbit of the hydrogen atom the value of n becomes equal to 3.
• Now, the total energy of nth shell of hydrogen atom is equal to -13.6/n² eV.
• The potential energy is equal to the double of the total energy.
• For n=3, total energy is equal to -1.51 eV and the potential energy is equal to -3.02 eV.