Question

number of waves made by a bohr electron in one complete revolution in 3rd Orbit​

Answer 1

Answer:In general, the number of waves made by a Bohr electron in an orbit is equal to its quantum number. Thus the circumference of the 3rd orbit is equal to 3 times the wavelength of electron i.e. the electron makes three revolution around the 3rd orbit.

Explanation:

Answer 2

.Number of waves = n(n - 1)/2 where n = Principal quantum number or number of orbit number of waves = 3(3 - 1)/2 = 3 * 2/2 = 3