Number of ways of allotting 30 marks to 10 questions so that each question gets atleast two marks is
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If 2 marks are already allotted to 10 questions, then 20 marks have already been allotted.
All that is left to do is give the remaining 10 marks between the 10 questions.
hence the remaining can be allotted in (n+r-1)C(r-1) ways.
here n=10,r=10
therefore 19C9 ways.
19!/(9!*10!)
All that is left to do is give the remaining 10 marks between the 10 questions.
hence the remaining can be allotted in (n+r-1)C(r-1) ways.
here n=10,r=10
therefore 19C9 ways.
19!/(9!*10!)
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