Question

Number of zeroes of polynomial 4x⁴+3²+7are?​

Answer 1

Solution:

Let p(x)=4x

4

−20x

3

+23x

2

+5x−6

If two of its zeroes are 2 and 3.

So, p(x)=4x

4

−20x

3

+23x

2

+5x−6

⇒p(x)=(x−2)(x−3)(4x

2

−1)

⇒p(x)=(x−2)(x−3)(2x−1)(2x+1)

For zeroes of polynomial, p(x)=0

(x−2)=0 or (x−3)=0 or (2x−1) or (2x+1)=0

x=2 or x=3 or x=

2

1

or x=

2

−1

Hence, all zeroes of the polynomial are 2,3,

2

1

and

2

−1

please mark as brainlist

Answer 2

Question-

Number of zeroes of polynomial 4x⁴+3²+7 are?​

Answer-

$x=\sqrt[4]{ -4}$

Explanation-

Finding zero(s) of an equation is putting that equation equal to zero and getting the variable value.

So,

$4x^{4} +3^{2} +7=0$

$\implies x=\sqrt[4]{ \frac{-7-9}{4}}$

$\implies x=\sqrt[4]{ \frac{-16}{4}}$

$\implies x=\sqrt[4]{ -4}$