Math, asked by gmeenish4, 9 months ago

Number of zeroes of the polynomial x^4 + x^3 + x^2+

x + I
is​

Answers

Answered by Satyam0107
0

Answer:

4

Step-by-step explanation:

according to the highest degree of the polynomial

Answered by tennetiraj86
0

Answer:

\huge{\boxed{\rm{\red{answer=4}}}}

Step-by-step explanation:

Given polynomial is x⁴+x³+x²+x+1

Given polynomial is x⁴+x³+x²+x+1The degree=4

Given polynomial is x⁴+x³+x²+x+1The degree=4It is a bi-quadratic polynomial.

Given polynomial is x⁴+x³+x²+x+1The degree=4It is a bi-quadratic polynomial.We know that The number of zeroes depends upon the degree of the given polynomial.

Given polynomial is x⁴+x³+x²+x+1The degree=4It is a bi-quadratic polynomial.We know that The number of zeroes depends upon the degree of the given polynomial.so, Degree = No. of zeroes

Given polynomial is x⁴+x³+x²+x+1The degree=4It is a bi-quadratic polynomial.We know that The number of zeroes depends upon the degree of the given polynomial.so, Degree = No. of zeroesNo. of zeroes =4

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