Question

Number of zeros in the polynomial X square + 6 x - 45
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Answer 1

Answer:

Let α,β be the zeroes of the given quadratic polynomial f(x)=x2+px+45

∴α+β=−p,αβ=45

It is given that, (α−β)2=144

⇒(α+β)2–4αβ=144

⇒(–p)2–4×45=144

⇒p2–180=144

⇒p2=144+180

⇒p2=324

⇒p=±324

∴p=±18