Question

number open open digit numbers divisible by 3 that can be formed using the digits 0 1 2 3 4 7 and 8 each digit is to be used at most one is N then find N/8​

Answer 1

Answer:

We've to make 5-digit numbers using given 7 digits exclud. ... 3 can be formed using the digits 0,1,2,3,4 ,7 and 8 if each digit is to be used atmost ... A four- digit number is formed using the digits

A number is divisible by 3 if the sum of its digits is divisible by 3. 375, for instance, is divisible by 3 since sum of its digits (3+7+5) is 15. And 15 is divisible by 3.

Rule: A number is divisible by 3 if the sum of its digits is divisible by 3. 375, for instance, is divisible by 3 since sum of its digits (3+7+5) is 15. And 15 is divisible by 3.

Answer 2

$\huge\star{\tt{\underline{\underline{\red{Answer\implies}}}}}\star$

Divisibility of 3 is sum of digits must has a factor 3

At Right given are the possible number made by the given digits

And on the left there are number of ways in which hey can be arranged