Question

number.
Q7 find that zeroes of the following quadrtic polynomials 6x²-7x-3​

Answer 1

Answer:

x=-1/3, 3/2

Step-by-step explanation:

6x²-7x-3

by splitting the middle term,

6x²-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

1) 3x+1=0

 3x=-1

  x=-1/3

2)2x-3=0

 2x=3

x=3/2