Question

number series 3+6+9+12...... to n terms​

Answer 1

Answer:

Method 1 (logic):

3,6,9,12,15,18,…. Is equivalent to 3(1,2,3,4,5,6…)

Tn (nth term) is 3n

Method 2 (sequences and series):

AP with common difference of 3 and first term 3, t1=3, tn= t1+(n-1)d= 3+(n-1)3= 3n

Explanation:

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