Number series
94,166,258,?,4912
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Given:
Number series
94, 166, 258, ?, 4912
To find:
Find the missing term of series 94, 166, 258, ?, 4912
Solution:
From given, we have a series,
94, 166, 258, ?, 4912
The series is solved as follows:
3^2 = 9 + 4 94
4^2 = 16 + 6 166
5^2 = 25 + 8 258
6^2 = 36 + 10 3610
7^2 = 49 + 12 4912
Therefore, the missing term of the series is 3610.
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