Question

Number split factorisation
25a2-64b2​

Answer 1

Answer:

Since both terms are perfect squares, factor using the difference of squares formula,

$a</p><p>2</p><p>−</p><p>b</p><p>2</p><p>=</p><p>(</p><p>a</p><p>+</p><p>b</p><p>)</p><p>(</p><p>a</p><p>−</p><p>b</p><p>)</p><p> where </p><p>a</p><p>=</p><p>5</p><p>a</p><p> and </p><p>b</p><p>=</p><p>8</p><p>b</p><p>.</p><p>(</p><p>5</p><p>a</p><p>+</p><p>8</p><p>b</p><p>)</p><p>(</p><p>5</p><p>a</p><p>−</p><p>8</p><p>b</p><p>)$

Answer 2

Answer:

(5a+8b)(5a-8b)

Step-by-step explanation:

25a²-64b²

= (5a)²-(8b)²

= (5a+8b)(5a-8b)

using formula x²-y² = (x+y)(x-y)