Question

Number System
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:​

Answer 1

Answer:

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Answer 2

Step-by-Step:

Let the first odd Integer be ( 2n + 1 ) where n is any Integer.

Therefore the next (consecutive) odd Integer is

( ( 2n + 1 + 2 ) or ( 2n + 3 )

Consequently the next odd Integer is

( 2n + 3 + 2 ) or ( 2n + 5 )

We are told:

Three times the first of three consecutive odd integers is 3 more than twice the third or:

3( 2n + 1 ) = 2( 2n + 5 ) + 3 so

( 6n + 3 ) = ( 4n +10 ) + 3 so

( 6n - 4n ) = ( 10 - 3 +3 ) or

( 2n ) = ( 10 )

Therefore ( n ) = ( 5 )

Although not asked, therefore

The first odd Integer is ( 2n + 1) = 11

The second odd Integer is ( 2n + 3 ) = 13

The third odd Integer is ( 2n + 5 ) = 15