Number when divided by 2 3 7 leaves a remainder 2 3 4 . Findr emainder when divided by 105
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Answer:
Step-by-step explanation:
Let x be the number,
x = 5 * a + 2
x = 3 * b + 2
x = 7 * c + 2
Where a, b and c are integers
For x to satisfy all the three equations x has to the LCM of 3, 5 and 7.
LCM ( 3, 5, 7 ) = 3 * 5 * 7 (as 3, 5 and 7 are co prime numbers and hence their LCM is a product of the 3 numbers)
So x =( 3 * 5 * 7) * a + 2
x = 105 * a + 2
Hence plug in the non negative integral values of a and get the series of number.
The smallest number is obtained when a = 1
Hence the first number is
x = 105 + 2
x = 107
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