Question

number x is selected from the numbers 1,2,3 and then a second number y is randomly selected from the numbers 4,5,9. What is the probability P(xy<9)

Answer 1

Answer:

Number x can be selected in three ways and corresponding to each such way there are three ways of selecting number y. Therefore, two numbers can be selected in 9 ways as listed :

(1,1),(1,4),(1,9),(2,1),(2,4),(2,9),(3,1),(3,4),(3,9)

So, total number of elementary events = 9

The product xy will be less than 9, if x, and y are chosen in one of the following ways :

(1,1),(1,4),(2,1),(2,4),(3,1)

Therefore, favourable number of elementary events = 5

Therefore, required probability =

9

5