Question

numberof digits in 2³² is .......... ( log 2 = 0.301 )

Answer 1

x = 2³²
Log x = 32 Log 2 = 9.632

x = 10⁹ * 10^0.632  

10^0.632 is between 1 and 10. but less than 10.

So there are 9 + 1  = 10 digits in x.