Question

numbers 1 to 10 are written on 10 separate balls the balls are kept in a box at random one ball is picked up what is the probability of getting a number greater than 7 and getting a one digit number

Answer 1

Total balls =10
No. of outcomes=10
Numbers greater than 7 =8,9,10
so 3 numbers are greater than 7
so (i) P(no. greater than 7)=
$\frac{number \: greater \: than \: 7}{total \: numbers}$
$\huge\bold{ \frac{3}{10}}$
One digit numbers = 1,2,3,4,5,6,7,8,9
outcomes=9
P(1 digit number )=
$\huge \bold{\frac{9}{10} }$