Question

Numbers 1 to 44 are written together what is remainder when divided by 45

Answer 1

1234...44/45

45=5*9

So now do it separately

123..44/5

= 4 remainder

Now to check divisibility of 3 add all the numbers

The number are from 0 to 9 (Sum of digits 45)

then 10 to 19 (Digit sum 45+1x10 = 55)

then 20 to 29 (Digit sum 45+2x10 = 65)

then 30 to 39 (Digit sum 45+3x10 = 75) and

then 40 to 44 (digit sum (10+4x5 = 30)

Therefore total digit sum come out to be (45+55+65+75+30 = 270)

270/9

= 0 remainder

So our answer is that number which leaves remainder 4 when divided by 5 & 0 when divided by 9.

Let that number be N

N/5 = 4 remainder

So N could be 5+4 = 9,14,19,...

N/9 = 0 remainder

N could be 9,18,...

The very first number common in both is 9

So remainder is 9

Answer 2

Sorry I don’t know this answer