Question

numbers
8. Divide 36 into four parts so that if 2 is added
to the first part, 2 is subtracted from the second
part, the third part is multiplied by 2, and the
fourth part is divided by 2, then the resulting
number is the same in each case.​

Answer 1

Answer:

let a,b,c,d be 4 numbers after dividing in to 4 parts.

now a+b+c+d=36

again a+2=b-2=c×2=d÷2

=>b-a=4,b=a+4

c=(a+2)/2

d=2(a+2)

now putting all these values in main eqn

a+a+4+(a+2)/2+2a+4=36

=>4a+8+(a+2)/2=36

=>9a+18=72

=>9a=54

*a=6

now b=a+4=6+4=10

again c=(a+2)/2=(6+2)/2=4

now d=2(a+2)=2(6+2)=2×8=16

______hope it will help you

Answer 2

Answer:

6, 10, 4, 16

Step-by-step explanation:

Let a, b, c & d be the four parts of 36

∴ a+b+c+d=36

Now, a+2=b-2=c×2=d÷2

∴b=a+4 ---eqn 1

c=(a+2)/2  ---eqn 2

d=2(a+2)    ---eqn 3

∴ a+b+c+d=a+(a+4)+(a+2)/2+2(a+2)  

36=a+a+4+a/2+1+2a+4

36=4a+a/2 + 9

9a/2=36-9=27

9a=54

a=6

∴b=6+4=10

c=(6+2)/2=4

d=2(6+2)=16

∴