Question

Numbers A, B and C are integral multiples of 3, 5 and 7 respectively.

If A is also divisible by 4 and C also divisible by 2, and ABC divisible by 16, then 'B' should also be divisible by​

Answer 1

Answer:

B should be dibide by 2

because , a×b×c=4×b×2=16

8b=16.

b=16/8

b=2

Answer 2

The numbers A, B, and C are, respectively, integral multiples of 3, 5, and 7.  B should be divisible by two if A is also divisible by four, C is also divisible by two, and ABC is divisible by sixteen.

B must be divided by two.

since $a b c = 4 b 2 = 16$

$8 \times b = 16$

$b=\frac{16}{8}$

$b=2$

The answer is 2

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