Question

Numbers A, B, C and D have 16, 28, 30 and 27 factors. Which of these could be a perfect cube?
A and B
B and C
A, B and C
B and D

Answer 1

Answer:

A & B can be a perfect cube

Step-by-step explanation:

Numbers A, B, C and D have 16, 28, 30 and 27 factors. Which of these could be a perfect cube?

A and B

B and C

A, B and C

B and D

I am assuming here factors of number A , B , C & D are prime factors

So to be a perfect cube

each factor should be at least 3 times

and there would be one factor 1 for each number which need to be subtracted

A  16 factors = 16 -1 = 15 = 5 * 3   can be a perfect cube

B 28 factors = 28 -1 = 27 = 9*3   - can be a perfect cu

C 30 factors = 30 -1 = 29 = 9*3 + 2    can not be a perfect cube

D 27 factors = 27 -1 = 26 = 8*3 + 2    can not be a perfect cube

A & B can be a perfect cube

Answer 2

Answer:

A & B can be a perfect cube

Step-by-step explanation: