numbers are formed by using all the digits 2,5,6,8,9 . How many of the numbers so formed is divisible by 2 or 5 (digits not repeated)
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Three digit number to be divisible by 5 , the last digit should be 5 or 0
_ _ _5
Two remaining places can be filled in 4×3=12
_ _ _0
Two remaining places can be filled in 3×3=9 (0 cannot be filled in the first place , it will become 2 digit number).
Total =12+9=21
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