Question

Numbers at zeros at polynomial
$p(x) = {x}^{2} - 10x + 16$
are three. True or false. ​

Answer 1

Answer:

true

Step-by-step explanation:

Let p(x)=x

4

+4x

3

−x

2

−16x−12=(x

2

−4)(x

2

−4x+3)

Zeroes of the polynomial =2,−1,−3

We know that if a is zero of a polynomial then it must satisfy p(a)=0

Now,

p(2)=(4−4)(2

2

+4×2+3)=0

p(−2)=(4−4)((−2)

2

+4×(−2)+3)=0

p(−1)=(1−4)((−1)

2

+4×(−1)+3)=0

p(−3)=(9−4)((−3)

2

+4×(−3)+3)=0

Since, p(2)=p(−2)=p(−1)=p(−3)=0

∴2,−2,−1, and −3 are zeroes the polynomial p(x).

Hence, A is the correct answer.