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In an examination Gita's marks are 2 more than 2/5 of Sita's marks Had Gita scored 4 marks less, she
would have got 3/8 of Sita's marks. Find their marks.
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Let Gita's marks be x
and Sita's marks be y
According to first condition,
Gita's marks= 2+ (2/5 of Sita's marks)
x= 2+ 2/5y
multiply overall by 5 ...
5x=10+2y
Rearranging..
5x-2y=10 .....(1)
According to second condition,
Gita's score - 4 = 3/8 of Sita's marks
x-4= 3/8 y
multiply overall by 8...
8x-32= 3y
Rearranging...
8x-3y= 32.......(2)
solving simultaneously (1)& (2)..
multiply equation (1) by 3 and equation (2) by 2..we get
15x-6y=30
16x-6y=64
- + -
------------------
-x = -34
x=34
substitute this value in (1)
5x-2y=10
5(34) -2y= 10
170 -2y= 10
-2y= 10-170
-2y= -160
y= 160/2
y= 80
hence ...Gita's marks is 34
and Sita's marks is 80 .
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