Numbers written from 3 to 101 and one number is selected find the probability of getting a number divisible by 3 and 5 will give brainlist answer if someone give correct answer
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So there are 1000 numbers evenly divisible by 3 between 3 and 3000 inclusive. Since 1 and 2 aren't evenly divisible by 3, there are also 1000 numbers divisible by 3 between 1 and 3000. So the probability is 1000/3000 = 1/3 that a random number picked from the set 1… 3000 is evenly divisible by 3.
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