Question

Numentul
Cos(AB)
Sin(A-C/2)Sin(B-C/2).Sin(C - B/2)
SinA/2. SinB/2.SinC/2
Then
the value of AC is.........
41. If in a triangle ABC sines of angles A and B satisfy the equation 4x2 -216 x+1
42. If O is the point inside the triangle ABC such that OBC = A/2, OCA= B/2, OAB = C/2 then​

Answer 1

Answer:

Sum of roots sinA+sinB =

c

a+b

=

sinC

sinA+sinB

sin(A)+sin(B)[1−

sinC

1

]=0

sinC=1

C=90

0

.

Hence,

sinA+cosA

=sinA+sinB

=

a

asinA

+

b

bsinB

=

c

sinC(a+b)

=

c

a+b

=

c

a+b