Question

Numerator of a fraction is 2 less than the denominator. If 1 added to the numerator and 3 to the denomination then the fraction become 2/3. find the original fraction

Answer 1

Answer:

7/9

Step-by-step explanation:

x-numerator, y-denominator

given:x=y-2

x+1/y+3=2/3

y-2+1/y+3=2/3(substitute the y-2 in x)

y-1/y+3=2/3

3(y-1)=2(y+3)

3y-3=2y+6

3y-2y=6+3

y=9

x=y-2

=9-2=7

x=7

fraction=7/9

Answer 2

Answer:

The original fraction is 7 / 9

Step-by-step explanation:

Let,

Numerator of a fraction = x

Denominator of a fraction = x + 2

If 1 added to the numerator = x + 1

3 added to the denominator = (x + 2 + 3)

x + 5

⇒ $\frac{x + 1}{x + 5} \: = \frac{2}{3}$

⇒ 3 (x + 1) = 2 (x + 5)

⇒ 3x + 3 = 2x + 10

⇒ 3x - 2x = 10 - 3

⇒ x = 7

★ Numerator of a fraction = 7

Denominator of a fraction = x + 2

⇒ 7 + 2

⇒ 9

★ Denominator of a fraction = 9

Therefore,

The original fraction is 7 / 9