Numerical 1:
The surface area of the floor of a room is 20 m and the height of its walls is
m. If the temperature in the room is 27° C and pressure is 1 atm, then find th
mass of air inside the room. Consider the mass of 1 mole of air to be 29 g.
(Given : 1 atm = 1.01 x 10'N m?- 1.01 x 10' Pa, R = 8.31) molk)
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Answer:
surface area ka formula use kro 2(lb+bh+hl) question m length breath and height dekho ans aa jayega
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