Question

numerical ........................​

Answer 1

Answer:

Average Speed= Total Distance÷Total time taken

Total Distance= 300×2=600 km

Total time taken= 6+4=10

Average Speed = 600÷10= 60 km/hr

Answer 2

Question :

A bus starting from Bengaluru covers a distance of 300km in 6 hours on Friday evening, and returns to Bengaluru in 4 hours early next morning. Find its average speed$.$

Solution :

❒ Average speed is defined as the ratio of total distance travelled to the time taken.

• It is a scalar quantity having only magnitude.
• It can't be negative or zero as term distance is included.
• SI unit : m/s
• CGS unit : cm/s
• Dimension formula : [L¹T‾¹]

Total distance travelled :

➛ d = d₁ + d₂

➛ d = 300 + 300

➛ d = 600 km

Total time taken :

➛ t = t₁ + t₂

➛ t = 6 + 4

➛ t = 10 hrs

Average speed of bus :

➠ v = d / t

➠ v = 600/10

➠ v = 60 km/hr