Numerical
A constant force is acting on a body of mass 3 kg changes its speed
from 2 m/s to 3.5 m/s in 15 second what is the magnitude of the force
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Answer:
F=0.3N
Explanation:
u=2m/s,. v=3.5m/s t=15sec. a=?
by using newton equation v=u+at
3.5=2+(a×15)
a=0.1m/s^2
so Magnitude of force F=ma
=3×0.1=0.3N
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