Question

Numerical:- A copper wire of length 2 m and area of cross section is 1.7 × 10^-6 m^2 and has a resistance of 2 × 10^-2 ohm.
Calculate the resistivity of copper?

Standard:- 10

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Answer 1

HELLO !!!!....

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●Given that :-
L = 2 m
A = 1.7 × 10^-6 m^2
R = 2 × 10^-2 ohm

● Using Relation :-

[note :- assume p = resistivity ]

=> R = pL/A

P = RA/L

$= \frac{2 \times {10}^{ - 2} \times 1.7 \times {10}^{ - 6}}{2} = 1.7 \times {10}^{ - 8} \: ohm - m$


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Hope it helps u !!!!

# Nikky

Answer 2

Hey mate here's your answer

Given L = 2m
A= 1.7 x 10^6 m^2
R = 2x10^2 ohm

So by ohms law

R = r x L/A
2x10^2 = r x 2/1.7x10^6
r = 2x10^2 x 1.7x10^6/2
r = 1.7 x 10^8 ohm.m

Hope it helps you