Science, asked by Xxitzurless45Xx, 15 hours ago

Numerical . A jeweller claims that he makes ornaments of pure gold that has a relative density of 19.3. He sells a bangle weighing 25.25 g to a person. The clever customer weighs the bangle when immersed in water and finds that it weighs 23.075 g in water. With the help of suitable calculations, find if the ornament is made of pure gold or not. ​ please help me


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Answers

Answered by s6c1548virendra7287
0

Explanation:

loss of weight in water = 25.250 - 23.075

= 2.175gf

loss of weight in water = mass of displaced water

= (volume of displaced water) × (density of water)

= 2.175gf

if we consider density of water

= 1

cc

g

, then,

volume of displaced water = volume of bangle = 2.175 cm

3

mass of bangle,

if it is made by pure gold of relative density 19.3 = 2.175 ×19.3

= 42 gf

Conclusion :-

Bangle is not made by pure gold of relative density 19.3

Answered by xxAjayxx
1

Answer:

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Explanation:

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