numerical : a train moves with a uniform velocity of 36 kmh power -1 For 10 s. find the distance travelled by it (100m)
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Answered by
8
36 km/h = 10m/s
If t = 10 s
Then distance = 100m
If t = 10 s
Then distance = 100m
Answered by
1
u=5/18 × 36=10 ms^-1
v=0
t=10s
v=u+at
0=10+a(10)
0=10+10a
10a=10
a=1ms^-2
s=ut+1/2at^2
s=(10)(10)+1/2(1)(10)^2
s=100+50
s=150
I HOPE IT WOULD BE CORRECT
v=0
t=10s
v=u+at
0=10+a(10)
0=10+10a
10a=10
a=1ms^-2
s=ut+1/2at^2
s=(10)(10)+1/2(1)(10)^2
s=100+50
s=150
I HOPE IT WOULD BE CORRECT
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