Question

Numerical:
In a lever a load of 600N is lifted by using 400N effort. if the load distance is 20 cm and the Ed is 40cm from the fulcrum. calculate efficiency.

Answer 1

Answer:

Load (l) = 680N

Effort (E) = 500N

Length of slope (l) = 12m

Height of slope (h) = 8 m

Now,

Output work = load * height

680 *8 = 5.44 *103 J

Input work = effort * length = 500 *12 = 6000J

Mechanical advantage (M.A) = loadeffort= 600500=1.36

Velocity ratio (V.R) =lh=128 = 1.5

Efficiency =M.A100%V.R= 90.6%

Answer 2

Answer:

Answer:

Load (1) = 680N

Effort (E) = 500N

Length of slope (I) = 12m

Height of slope (h) = 8 m

Now,

Output work = load * height

680 *8 = 5.44 *103 J

Input work = effort * length = 500 *12 = 6000J

Mechanical advantage (M.A) = loadeffort= 600500-1.36

Velocity ratio (V.R) =Ih=128 = 1.5

Efficiency =M.A100%V.R= 90.6%