Question

Numerical on motion velocity speed and acceleration

Answer 1

Answer:

problem:

An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.

solution:a = +3.2 m/s2

a = +3.2 m/s2t = 32.8 s

a = +3.2 m/s2t = 32.8 svi = 0 m/s

a = +3.2 m/s2t = 32.8 svi = 0 m/sFind:

a = +3.2 m/s2t = 32.8 svi = 0 m/sFind:d = ??

a = +3.2 m/s2t = 32.8 svi = 0 m/sFind:d = ??d = vi*t + 0.5*a*t2

a = +3.2 m/s2t = 32.8 svi = 0 m/sFind:d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s2)*(32.8 s)2

a = +3.2 m/s2t = 32.8 svi = 0 m/sFind:d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s2)*(32.8 s)2d = 1720 m

Explanation:

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