Question

numerical physics... ​

Answer 1

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TO FIND

Distance and displacement.

According to the question,

The rectangular track is 30m broad and 40m wide.

The person starts from one corner and reaches the opposite corner

Hence,

Distance = ½ of perimeter.

Perimeter = $\boxed{2(l+b)}$

=> 2(30+40)

=> 2(70)

=> 140m

Distance = ½ × 140 = 70 cm

Displacement = Diagnol of rectangle

Let diagnol = x

The diagnol is like a hypotenuse

x² = 30² + 40²

x² = 900 + 1600

x² = 2500

x= √2500

x = 50cm

Hence,

Distance : 70 cm

Displacement : 50 cm