Question

Numerical Problem 3
A bullet of mass 20 g moving with a velocity of 200 ms, gets embedded in freely suspended
wooden target of mass 480 g. Calculate the velocity of the wooden target on being hit.​

Answer 1

Answer:

2ghis equal to vf2-vi2

Explanation:

this formula is used for this problem

Answer 2

Use Momentum conservation
Ui of bullet = 200m/s
Ui of block = 0
Pi of bullet = 20*200=4000
Pf of whole embedded system will be = 480+20 * some velocity V
By LMC(Linear momentum conservation )
Pi=pf
4000=500*V
V = 8m/s