NUMERICAL PROBLEM
Calculate the amount of work done, when a force of 25 N displaces a
body through 10 m, in its own its direction.
Answers
Explanation:
given:
•force applied = 25N
•displacement = 10m
to find:
•work done.
solution:
since the work done and displacement is along the same direction
(let us assume positive x-axis)
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the angle between the two wouldbe 0°.
we will use the formula to calculate work done:
\underline{\underline{\boxed{\red{\tt work=force×displacement}}}}
work=force×displacement
placing values which are known in the above equation,
\tt work=(25)(10)work=(25)(10)
\tt work = 250work=250
SI unit:
•the S.I units of force and distance are Newton and metre respectively
•collectively, the SI unit of work would be Newton metre.
•newton metre is also called as Joule represented as J
so, the work done is :
\boxed{\blue{\tt work = 250J }}
work=250J
hope this helps!!
Answer:
given:
•force applied = 25N
•displacement = 10m
to find:
•work done.
solution:
since the work done and displacement is along the same direction
(let us assume positive x-axis)
the angle between the two wouldbe 0°.
we will use the formula to calculate work done:
work=force×displacement
placing values which are known in the above equation,
work=(25)(10)work=(25)(10)
work = 250work=250
SI unit:
•the S.I units of force and distance are Newton and metre respectively
•collectively, the SI unit of work would be Newton metre.
•newton metre is also called as Joule represented as J
so, the work done is :
work=250J