Question

NUMERICAL PROBLEM

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temperature of a metal ball is 45°C. When an energy of 4000J is supplied its temperature rises by 50°C. Calculate its heat capacity.​​

Answer 1

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• Energy = m × s × ∆T = 4000 J .

• Heat capacity = m × s

• ∆T = 45°

Substituting values ..

4000 J = ms × 50°

Heat capacity = 4000 / 50

Heat capacity = 80

Answer 2

Explanation:

E = m × s × ∆T = 4000 J .

Heat capacity = m × s

∆T = 45°

Substituting values=

4000 J = ms × 50°

Heat capacity = 4000 / 50

Heat capacity = 80