Question

Numerical Problems
1.
Find the amount of work done when a body moves at a distance of 2 m by the
application of 200 N force.
(Ans: 4000 Joule)
An ho moying with the yelocity of 20​

Answer 1

$\LARGE{\bf{\underline{\underline{GIVEN:-}}}}$

• Distance (s) = 2 m.
• Force (F) = 200 N.

$\LARGE{\bf{\underline{\underline{TO \ FIND:-}}}}$

• Work done.

$\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}$

We know that:

$\boxed{\sf{\red{W=Fs}}}$

Where:

• W is work.
• F is Force.
• s is Distance.

Substitute the values.

$\sf \to W=200 \times 2$

$\mapsto \sf{\red{W=400 N.}}$

∴ The answer should be 400 N.

KINEMATIC EQUATIONS OF MOTION:

$\boxed{\substack{\displaystyle \sf v=u+at \\\\ \displaystyle \sf s=ut+\dfrac{1}{2}at^2 \\\\ \displaystyle \sf 2as=v^2-u^2}}$

Answer 2

Answer:

W = 400 J

Explanation:

W = Force * distance

W = 200 * 2

W = 400