NUMERICAL PROBLEMS ON CHARLES' LAW : 279 cm of gas at 87 °C is cooled to standard temperature, at constant pressure. Calculate the volume of gas at standard temperature.
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Given:
Initial Volume of a gas (V₁) = 279 cm³
Initial Temperature (T₁) = 87 + 273 = 360° K
Final Temperature (T₂) = 273° K
[ standard temperature of a gas is 273.15° K ≈ 273° K ]
Let the final volume (V₂) = V cm³.
We know that,
Charle's law of gases states that at constant pressure the Volume of a gas is directly proportional to the temperature.
→ V ∝ kT
→ V/T = K
→ V₁/T₁ = V₂/T₂
→ 279/360 = V/273
→ 279 * 273 = 360 * V
→ 279 * 273/360 = V
→ 211.5 cm³ = V
Therefore, the volume of the gas decreases to 211.5 cm³ when it is cooled to standard temperature.
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