Question

Numerical: Q1. A bus between city A and city B passes 100 km, 160 km, 220 km points at 10:30 am, 11:30 am and 1:30 pm respectively. If bus has started its journey from city A at 8:00 am and reached city B at 3:00 pm which is 280 km away from city A. Find average speed of bus a) During the interval 10:30 am to 11:30 am b) 10:30 am to 1:30 pm c) 8:00 am to 3:00 pm​

Answer 1

$\sf\large \green{\underbrace{\red{Answer⋆}}}:$

The bus had already reached 100 at 10:30, the beginning time. Thus, the actual distance travelled during the given duration will be 220- 100 = 120. From 10:30 to 11:30, It is 1 hour.

Explanation:

$\huge \underbrace \mathfrak \blue{@ItzGeniusMunda}$

Answer 2

Correct option is

A

60 km/h

The distance covered between 10.30 am to 11.30 am is 160km−100km=60km.

The time interval is 1 hour. The average speed during this interval is

v

1

=

1h

60km=60km/hr