Question

Numerical: Q1. A bus between city A and city B passes 100 km, 160 km, 220 km points at 10:30 am, 11:30 am and 1:30 pm respectively. If bus has started its journey from city A at 8:00 am and reached city B at 3:00 pm which is 280 km away from city A. Find average speed of bus a) During the interval 10:30 am to 11:30 am b) 10:30 am to 1:30 pm c) 8:00 am to 3:00 pm A 100 km 160 km 220 km B 8:00 am 10:30 am 11:30 am 1:30 pm 03:00 please tell full answers ​

Answer 1

Appropriate Question

A bus going from city A to city B passed the 100 km, 160 km and 220 km points at 10.30 am, 11.30 am and 1.30 pm. Find the average speed of the bus during the following interval :

(i) Between 10:30 am to 11:30 am

(ii) Between 10:30 am to 1:30 am

(iii) Between 11:30 am to 1:30 am

Answer

(i) 160 - 100 = 60km

Avg. Speed during this interval is

$\sf{S = \frac{D}{T} }$

$\sf{V_1 = \frac{60km}{1hr} = 60km/h}$

(ii) 220 - 160 = 60km

Avg. Speed during this interval is

$\sf{V_2 = \frac{60km}{2hr} =30km/h }$

(iii) 200- 100 = 120km

Avg. Speed during this interval is

$\sf{V_3 = \frac{120km}{3hr} = 40km}$

Answer 2

Answer:

The distance covered between 10.30 am to 11.30 am is 160km−100km=60km.

The time interval is 1 hour. The average speed during this interval is

v

1

=

1h

60km

=60km/hr