Question

Numerical
question 1
A microscope is provided with a man scale graduated with 20 division in 1 cm and a vernier scale with 50 divisions on it of lenght same as of 49 divisions of man scale. find the least count of the microscope ?

{ANS : 0.001 CM }​

Answer 1

$\huge\bold\red{AnsweR :-}$

__________

50 divisions of vernier scale = 49 divisions of main scale.

or , 1 division of vernier scale = 49/50 divisions of main scale.

or, 1 division of vernier scale = 0.98 division of main scale.

so, least count of vernier scale =

1 main scale division - 1 vernier scale division.

= 1 main scale division - 0.98 main scale division.

= 0.02 main scale division.

________

☆GIVEN :-

1 main scale division = 1/20 cm.

so, least count of microscope = 0.02 × 1/20

= 0.01/10

= 0.001 cm.

⭐hence, least count of microscope is 0.001 cm.

__________________♡

Answer 2

50 divisions of vernier scale = 49 divisions of main scale.

or , 1 division of vernier scale =

$\frac{49}{50}$

divisions of main scale.

or, 1 division of vernier scale = 0.98 division of main scale.

so, least count of vernier scale =

1 main scale division - 1 vernier scale division.

= 1 main scale division - 0.98 main scale division.

= 0.02 main scale division.

________

GIVEN :-

1 main scale division =

$\frac{1}{20}$

cm.

so, least count of microscope = 0.02 ×

$\frac{1}{20}$

=

$\frac{0.01}{10}$

= 0.001 cm.

hence, least count of microscope is 0.001 cm.

__________________