Numerical Questions
1. If a stone is dropped from the height 100 m. What is its speed at the time of
collision with the earth. (g =9.8 m/s).
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Answer:
This is a case of a freely falling body so we have to neglect the effect of air resistance.
The initial speed Vi of the stone = 0 m/s and its final speed v is the one to be solved.
The formula was derived from 1/2 * m * v^2 = m * g * h and after canceling m we get this
formula to be used v^2 = 2 * g * h and substituting values v^2 = 2 * 9.8 m/s^2 * 100 m Continuing v^2 = 19.6 m/s * 100 m; v^2 = 1960 (m/s)^2. We then extract the square root of this value to get ihe speed of the stone.
The speed of the stone v = 44.27 m/s.
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