Question

Numerical value of vector A = 4i - 3j + 5k is ? options: a) 5√2,,,, b) 2,,, c) 6√3,,,d) 0

Answer 1

Answer:

5√2

Explanation:

we have formula to find out the magnitude of vectors is √ a^2+b^2+2abcos theta

Answer 2

Explanation:

Given that:Numerical value of vector A = 4i - 3j + 5k is ? options: a) 5√2,,,, b) 2,,, c) 6√3,,,d) 0

To find: Numerical value of vector A

Solution:

To find Numerical value of vector A,

find the magnitude of the vector

$\vec A = 4i - 3j + 5k \\ \\ | \vec A| = \sqrt{( {4)}^{2} + ( {3)}^{2} + ( {5)}^{2} } \\ \\ | \vec A| = \sqrt{16 + 9 + 25} \\ \\ | \vec A| = \sqrt{50} \\ \\ | \vec A| = 5 \sqrt{2}$

Thus,

Numerical value(Magnitude) of given vector is 5√2.

Hope it helps you.