Numerical-What is the weight of a body having mass 50 kg at a height of 3200 km from the surface of the earth,if the mass of the earth is 6×10power24 kg and its radius is 6400kg?
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Answered by
1
Answer:
217.25
Explanation:
Let g’ be the value of g at a height h above the surface of the earth. Then,
g’=GM/(R+h)^2
where R is the radius of the earth. This can also be written as
g’=(GM/R^2)/(1+h/R)^2 = g/(1+h/R)^2
where g is the value of f at the earth’s surface. Here g is given by
g=6.67*10^-11*6*10^24/6400000^2 = 9.776 m/s^2
So,
h’=9.776/(1+3200/6400)^2 = 217.25 m/s^2
weight = 217.25
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2
Answer:
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Explanation:
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