Physics, asked by KristinaStha01, 1 month ago

Numerical-What is the weight of a body having mass 50 kg at a height of 3200 km from the surface of the earth,if the mass of the earth is 6×10power24 kg and its radius is 6400kg?

Answers

Answered by rajaswanik
1

Answer:

217.25

Explanation:

Let g’ be the value of g at a height h above the surface of the earth. Then,

g’=GM/(R+h)^2

where R is the radius of the earth. This can also be written as

g’=(GM/R^2)/(1+h/R)^2 = g/(1+h/R)^2

where g is the value of f at the earth’s surface. Here g is given by

g=6.67*10^-11*6*10^24/6400000^2 = 9.776 m/s^2

So,

h’=9.776/(1+3200/6400)^2 = 217.25 m/s^2

weight = 217.25

Answered by Celestria
2

Answer:

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Explanation:

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