NUMERICALS
1. A kangaroo can jump 2.5 m vertically. What must be
the initial velocity of the kangaroo? for 9std state board full solve sum
Answers
Answered by
2
Using third equation of motion,
v^2 = u^2 + 2as
v is equal to zero since velocity at highest point = 0
0 = u^2 + 2 ( - 9.8 ) × 2.5
0 = u^2 - 49
u^2 = 49
u = √49
u = 7 m/sec
ANSWER = 7 m/sec
Answered by
0
Answer:
The initial velocity of the kangaroo must be 7 m/s.
Explanation:
a = 9.8 m/s²
s = 2.5 m
v = 0 m/s
v² = u² + 2as
=> (0)² = u² + 2 * (-9.8) * 2.5
=> 0 = u² - 5 * 9.8
=> 0 = u² - 49
=> u² = 0 + 49
=> u² = 49
=> u = 7 m/s
So,
The initial velocity of the kangaroo must be 7 m/s.
Here, negative sign of acceleration shows that it is in the opposite direction of the velocity.
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