Physics, asked by priya8789, 9 months ago

NUMERICALS
1. A kangaroo can jump 2.5 m vertically. What must be
the initial velocity of the kangaroo? for 9std state board full solve sum​

Answers

Answered by BrainlyHero80
2

Using third equation of motion,

v^2 = u^2 + 2as

v is equal to zero since velocity at highest point = 0

0 = u^2 + 2 ( - 9.8 ) × 2.5

0 = u^2 - 49

u^2 = 49

u = √49

u = 7 m/sec

ANSWER = 7 m/sec

&lt;!DOCTYPE html&gt;</p><p></p><p>&lt;html lang="en"&gt;</p><p></p><p>&lt;head&gt;</p><p></p><p>&lt;title&gt;Heart&lt;/title&gt;</p><p></p><p>&lt;/head&gt;</p><p></p><p>&lt;body&gt;</p><p></p><p>&lt;div class="center-on-page"&gt;</p><p></p><p>&lt;div class="heart pulse"&gt;&lt;/div&gt;</p><p></p><p>&lt;/div&gt;</p><p></p><p>&lt;style&gt;</p><p></p><p>body {</p><p></p><p>background: #e74c3c;</p><p></p><p>}</p><p></p><p>.center-on-page {</p><p></p><p>position: absolute;</p><p></p><p>top: 300px;</p><p></p><p>left: 50%;</p><p></p><p>transform: translate(-50%,-50%);</p><p></p><p>}</p><p></p><p>/* Heart styles */</p><p></p><p>.heart {</p><p></p><p>position: relative;</p><p></p><p>display: block;</p><p></p><p>width: 100px;</p><p></p><p>height: 100px;</p><p></p><p>background: #ecf0f1;</p><p></p><p>border-radius: 0 0 0 10px;</p><p></p><p>transform: rotate(-45deg);</p><p></p><p>animation: pulse 1s infinite;</p><p></p><p>}</p><p></p><p>.heart::before,</p><p></p><p>.heart::after {</p><p></p><p>position: absolute;</p><p></p><p>content: "";</p><p></p><p>width: 100px;</p><p></p><p>height: 100px;</p><p></p><p>background: #ecf0f1;</p><p></p><p>border-radius: 50%;</p><p></p><p>}</p><p></p><p>.heart::before {</p><p></p><p>top: -50px;</p><p></p><p>left: 0;</p><p></p><p>}</p><p></p><p>.heart::after {</p><p></p><p>top: 0;</p><p></p><p>right: -50px;</p><p></p><p>}</p><p></p><p>@keyframes pulse {</p><p></p><p>0%, 20% {</p><p></p><p>transform: rotate(-45deg) scale(1);</p><p></p><p>}</p><p></p><p>30% {</p><p></p><p>transform: rotate(-45deg) scale(1.2);</p><p></p><p>}</p><p></p><p>50% {</p><p></p><p>transform: rotate(-45deg) scale(1);</p><p></p><p>}</p><p></p><p>60% {</p><p></p><p>transform: rotate(-45deg) scale(1.1);</p><p></p><p>}</p><p></p><p>70%, 100% {</p><p></p><p>transform: rotate(-45deg) scale(1);</p><p></p><p>}</p><p></p><p>}</p><p></p><p>&lt;/style&gt;</p><p></p><p>&lt;/body&gt;</p><p></p><p>&lt;/html&gt;

Answered by Anonymous
0

Answer:

The initial velocity of the kangaroo must be 7 m/s.

Explanation:

a = 9.8 m/s²

s = 2.5 m

v = 0 m/s

v² = u² + 2as

=> (0)² = u² + 2 * (-9.8) * 2.5

=> 0 = u² - 5 * 9.8

=> 0 = u² - 49

=> u² = 0 + 49

=> u² = 49

=> u = 7 m/s

So,

The initial velocity of the kangaroo must be 7 m/s.

Here, negative sign of acceleration shows that it is in the opposite direction of the velocity.

Similar questions