Question

Numericals:
1. A wooden trolley of mass 3 kg is mounted on wheels on horizontal rails. Neglecting
friction and air resistance, what will be the final velocity of the trolley if a bullet of mass
2 gm is fired into it with a horizontal velocity of 800 m/s along the direction of the rails.
(Ans. 0 = 0.53 m/s
annlied to a body of mass 60 kg moving initially with​

Answer 1

Explanation:

Since the hole is on the floor , that means sand is falling vertically with respect to trolley. Therefore there is no force in horizontal direction hence in horizontal direction momentum is conserved.

Let M= mass of trolley

     m= mass of sandbag

     v1= initial velocity 

     v2= final velocity ( to be found)  

Then P1=(M+m)v1 when the sand bag is empty the momentum is 

P2=(M+0)v2

Momentum is conserved in horizontal direction so

P1=P2

⇒=v2=M(M+m)v1=300300+25×27×185=8.215m/s

PLS MARK AS BRILLIENT AND GIVE ME 5 STARS

Answer 2

Answer:

Let the mass of wooden trolley,M=3 Kg

And the mass of bullet,m=2 gm=0.002 Kg

Initial velocity of the bullet,u=800 m/s

Final velocity of the trolley,v=?

According to the deduction of Newton's First Law,

Mv=mu

3Kg × v = 0.002Kg × 800m/s

v = 0.002Kg × 800m/s / 3Kg

v = 2 × 800m/s / 3 × 1000

v = 16 m/s / 30

v= 0.53 m/s

Therefore,final velocity of the trolley is 0.53 m/s