Question

NUMERICALS
1. An iron ball of mass 4 kg is stationary on a floor. The area of the point of contact between
the ball and the floor is 0.25 m3. Find the pressure exerted by the ball on the floor.​

Answer 1

Given:-

• Mass of iron ball (m) = 4kg

• Area of contact between the ball and the floor is 0.25m³

To Find:-

• Pressure exerted by the ball (p) .

Solution:-

As we know that the product of mass and acceleration due to gravity is called weight of the object.

→ W = mg

substitute the value we get

→ W = 4×10

→ W = 40N

And Now

→ Pressure = Force /Area

→ p = F/a

→ p = w/a

substitute the value we get

→ p = 40/0.25

→ p = 160 Pa. or 160N/m²

∴ The pressure acting on the floor by the ball is 160 Pascal.

Answer 2

Given :-

• Mass (m) = 4kg
• Area (a) = 0.25m³

To Find :-

• The pressure (p) exerted by the ball.

Solution :-

As we know that,

F = w = mg

↪ F = W = 4 × 10 [ g = 10m/s² ]

↪F = W = 40N.

☀ Finding the pressure exerted by the ball. ☀

↪ P = F/A

↪ P = 40/0.25

↪ P = 160pa [ N/m² = Pascal ]

.°. Pressure is 160pa.