Question

Numericals :-
a) Calculate the amount of work done when a force of 25N displaces a body through 1500 cm, in its own
direction.
b) A boy does a work of 800Joule in dragging a sack of rise through a distance of 16m. What is the magnitude of force applied by the boy.​

Answer 1

Explanation:

$\tt Question \: A \\ \\ \tt Force\:(F) = 25\: N \\ \tt Displacement\:(s) = 1500\: cm = 15\: m \\ \\ \tt We\:know\:that \\ \\ \tt Work\: done = F.s \\ \\ \tt \longrightarrow W = 25 × 15 \\ \\ \tt \longrightarrow W = 375 \:J \\ \\ \boxed{\bold{\red{\tt Work\:done\:is\:375\:Joule}}} \\ \\ \tt Question \: B \\ \\ \tt Work \:done\:(W) = 800 Joule \\ \tt Displacement\:(s) = 16 m \\ \\ \tt We \:know\:that \\ \\ \tt W = F.s \\ \\ \tt \longrightarrow 800 = F × 16 \\ \\ \tt F = \frac{800}{16} \\ \\ \tt F = 50 N \\ \\ \boxed{\bold{\red{\tt Force\: applied\:by\:the\:boy\:is\:50\:N}}}$